Tuesday, October 12, 2021

Carbon and its Compounds | Class 10 | Activity 4.9 with Solution

Carbon and its Compounds | Activities in Text Book with Solution

Activity 4.9

Set up the apparatus as shown in Chapter 2, Activity 2.5.

Take a spatula full of sodium carbonate in a test tube and add 2 mL of dilute ethanoic acid.

What do you observe?

✅ Answer: Following reaction occurs:

2CH3COOH + Na2CO3 → 2CH3COONa + CO2 + H2O

                   (Sodium acetate)


Pass the gas produced through freshly prepared lime-water. What do you observe?

✅ Answer: Lime-water turns milky. It means that the gas is CO2.

Can the gas produced by the reaction between ethanoic acid and sodium carbonate be identified by this test?

✅ Answer: Yes. The gas is CO2.

Repeat this Activity with sodium hydrogen carbonate instead of sodium carbonate.

✅ Answer: Reaction with sodium hydrogen carbonate:

CH3COOH + NaHCO3 → CH3COONa + H2O + CO2


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