Set up the apparatus as shown in Chapter 2, Activity 2.5.
Take a spatula full of sodium carbonate in a test tube and add 2 mL of dilute ethanoic acid.
What do you observe?
✅ Answer: Following reaction occurs:
2CH3COOH + Na2CO3 → 2CH3COONa + CO2 + H2O
Pass the gas produced through freshly prepared lime-water. What do you observe?
✅ Answer: Lime-water turns milky. It means that the gas is CO2.
Can the gas produced by the reaction between ethanoic acid and sodium carbonate be identified by this test?
✅ Answer: Yes. The gas is CO2.
Repeat this Activity with sodium hydrogen carbonate instead of sodium carbonate.